Question

Optimization problem attached

Answer 1

I knew rld would come here

Answer 2

LOL

Answer 3

\[A=xy\]
\[3x+2y=720\]
\[2y=720-3x\]
\[y=360-\frac{3}{2}x\]
\[A(x)=x(360-\frac{3}{2}x)=360x-\frac{3}{2}x^2\] vertex is at
\[-\frac{b}{2a}\] etc

Answer 4

or if this is calculus class "take the derivative, set it equal zero and solve"
you will still get
\[-\frac{b}{2a}\] here it is
\[\frac{360}{3}=120\] for x

Answer 5

can u come help me?

Answer 6

so teh asnwer is c) 180 by 120 feet with the divider 120 feet long? is tath wat u mean by 120

Answer 7

This problem can be solved in one step with Mathematica's "Maximize" function.
x*y is the area to be maximized, subject to the constraint that 3x+2y=720 and x and y are the variables.

Maximize[ { x y, 3 x + 2 y = 720 }, {x,y} ] -> {21600, {x = 120, y = 180}}
21600 is the maximum area, and x and y are 120 and 180 respectively.

3*120 + 2*180 = 720