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Find y' if sin(x+y) = sin(x) + sin(y)
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hi
hi AravindG
that's not true
LOL
The derivative is the following: cos(x+y) * (1+y') = cos(x) + cos(y) * y' Then just rearrange to isolate y': y' * cos(x+y) + cos(x+y) = cos(x) + cos(y) * y' y' * cos(x+y) - y' * cos(y) = cos(x) - cos(x+y) y' [cos(x+y) - cos(y)] = cos(x) - cos(x+y) y' = [cos(x) - cos(x+y)]/[cos(x+y) - cos(y)]
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Also imranmeah91 is technically right...
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