Find the vertex
line of symmetry
max/min value
1/3(x+8)^2+8

Question

Find the vertex 
line of symmetry
max/min value 
1/3(x+8)^2+8

mertsj · Answer

The vertex is (-8,8)   The line of symmetry is a vertical line that goes through the vertex so its equation is x = -8.  This parabola is concave upward and has a minimum point.  That minimum point is the vertex.  So the lowest y value is 8 and that is the minimum.

anonymous · Answer

how do you find the vertexr when it is 1/3

mertsj · Answer

The 1/3 is the a value.  Here is the vertex form of a parabola:
$$y = a (x-h)^{2} + k  $$  In this equation the vertex is (h,k)  Match your equation up with this equation.  You will see that h = -8 and k = 8  so the vertex is (-8,8)

mertsj · Answer

The 1/3 is the a value and it tells you how "fat" or "skinny" the parabola is.  If the a value is small, the parabola will be fatter.  Also if a is negative, the parabola is concave downward.