Question

Use the Pythagorean Theorem to find the missing side of the triangle. Round your solution to the nearest tenth, if necessary.


A. 20
B. 25
C. 26
D. 30

Answer 1

Alright I got a bit confused.. ah any takers to help me out? Step by step?

Answer 2

\[\large c^2 = a^2 + b^2\]

Answer 3

a and b are the flat edges

Answer 4

take the square root of the squared version of them to find c

Answer 5

It doesnt matter if you make a=24 or a = 7.. You get the same answer regardless.

Answer 6

you have 2 square them and then add them and then take the square root of them

Answer 7

What ever you decide to make a, then b is the one you didnt choose.

Answer 8

We will make a = 24 and b = 7\[\large c^2 = 24^2 + 7^2\]

Answer 9

see if she can figure it from here

Answer 10

The legs (short sides) are 7 and 24. You can call either one of them a and the other one is b.

Answer 11

\[\large c^2 = 576 + 49\] Since C is squared we need to get just C.. So take the square root on both sides.\[\large \sqrt{c^2} = \sqrt{576 + 49}\] The square root cancels out the C squared leaving you with just C\[\large C = \sqrt{576 + 49}\]

Answer 12

correct

Answer 13

Alright. Well like I was confused on this on the last problem because I kind of figured it was going to be similar to the other question I posted previously to this one considering they're both the Pythagorean Theorem, and I had said that I wrote the steps down for that problem and I was going over it so I knew how to do that for this problem but I was really confused as to how to get the answer for like: \[a ^{2}+5^{2}=8^{2}\] and then how to get \[a ^{2}+25=64\]
Would A be considered as 1?

Answer 14

no, you just simplify and move the 25 over so that you can get a^2 by itself

Answer 15

No. You solve for a by subtracting 25 from both sides. The you get a^2 = 39. Then take the square root of both sides to get that x = sqrt39

Answer 16

yurp

Answer 17

Okay so, so far I did this to the problem:
\[c ^{2}+7^{2}=24^{2}\]
\[c ^{2}+49=576\]
\[c ^{2}=527\]
Is that incorrect or is there any way I could do that? But the big question I have about this is now what do I do that I have that final answer?

Answer 18

to get the final answer*

Answer 19

No. The legs are 7 and 24. They are a and b. You are being asked to find the hypotenuse which is c.

Answer 20

Okay so my equation would like this: \[24^{2}+7^{2}=c ^{2}\]?

Answer 21

look*

Answer 22

Okay so since I switched that around, I now have: \[527=c ^{2}\]
How do I find the square root of that to get my final answer? That is the one I am really confused on now.

Answer 23

Anyone there?

Answer 24

How did you get c^2 = 527??

isn't it 7^2 + 24^2 = c^2 ?
7*7 = 49
24*24= 576
add them together

Answer 25

That's what c^2 equals so far and then I have to find the square root of 527 and round it to the nearest tenth...

Answer 26

yes

Answer 27

Check your math.

Answer 28

Wait Mertsj who are you saying yes to? Me or phi?

Answer 29

Add 49 and 576 again. You will not get 527

Answer 30

Okay so c\[c ^{2}=625\] but now how do I find the square root of that?

Answer 31

You could use a calculator
or you could test the answers

Answer 32

or you could factor 625 and look for pairs of numbers

Answer 33

or you could have memorized it (many people do!)

Answer 34

or type sqrt(625) in the google search window