write an equation of the line that passes through the point (-4, -1) and is (a) parallel to and (b) perpendicular to the line 2x + 7y = 14
ok so first you need to put the equation in standard form
y=mx+b
how do i do that?
the equation they give you is 2x+7y=14 so you have to move the y's all to one side making it 7y=-2x+14
then you have to divide by 7 to get rid of the coefficient in front of the y
so -2/7x + 2?
yes! now for the next part
it says it first needs to be PARALLEL do you know what a parallel slope implies?
parallel --> same slope perpendicular --> negative reciprocal slope
ok
in the equation of a line y=mx+b, m is the slope so, parallel --> -2/7 perpendicular --> 7/2
with me so far?
yes
(-4,1) are the coordinates so -4=x and 1=y now all you have to do is plug them both into the equation y=mx+b to find b
for example, 1=(-2/7)(-4) + b
b happens to come out to -1/7
now, you write it as y=-2/7x - 1/7
that's for parallel slope you have to do it with the negative reciprocal slope if you want perpendicular
so whats the answer for parallel?
nvm i got it
i just wrote it for you above
i didn't seen that post thank you
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