Question

Solve for z: -2+(z-5)^2/3=6

Answer 1

1) add 2
2) cube both sides
3) take the square root

Answer 2

is this
\[-2+(z-5)^{\frac{2}{3}}=6\] or
\[-2+(z-5)^{\frac{3}{2}}=6\]

Answer 3

1) add 2
2) multiply by 3
3) square root (remember + and -)
4) add 5

Answer 4

The first one.

Answer 5

@satellite73 powers have a higher order than division

Answer 6

aaaaand the asker mistyping the question strikes again!

Answer 7

mistyping the question? how so....

Answer 8

If you wanted it the same as satellite's first equation you needed a bracket around the 2/3

Answer 9

There is no brackets in the original problem so therefore I can not put it on there if it is not there. That then would be mistyping the question.

Answer 10

you didnt use superscripts though which would be present in your question. using brackets stops the need for superscripts.

Answer 11

\[-2+(z-5)^{\frac{2}{3}}=6\]
\[(z-5)^{\frac{2}{3}}=8\]
\[(z-5)^2=8^3=512\]
\[z-5=\pm\sqrt{512}=\pm16\sqrt{2}\]
\[z=5\pm16\sqrt{2}\]

Answer 12

that is if it was
\[-2+(z-5)^{\frac{2}{3}}=6\]

Answer 13

if it was
\[-2+(z-5)^{\frac{3}{2}}=6\] then
\[(z-5)^{\frac{3}{2}}=8\]
\[\sqrt{z-5}=2\]
\[z-5=4\]
\[z=9\]

Answer 14

Satellite; thank you for your help. I got the same answer I was working on it. :)