Question

.

Answer 1

yes

Answer 2

ask a question if you have one

Answer 3

Yes i can help u as well

Answer 4

pretty sure we can :) post one

Answer 5

yes the one u posted before? lemme check it :D

Answer 6

newton, leibniz, even fermat

Answer 7

Lagrange

Answer 8

i am sorry i cant get this one. probably some 1 else will help you :)

Answer 9

we can do this

Answer 10

think we just have to think simple, not hard. put area of base as A
and height as h and volume as
\[Ah=500\]

Answer 11

and therefore
\[h=\frac{500}{A}\] now you know that
\[A'=3\] and you want
\[h'\] so we get
\[h'=-\frac{500A'}{A^2}\]

Answer 12

now plug in the numbers
the sides are 18 so the area of the base is
\[A=18^2=324\] and so we get
\[h'=\frac{-500\times 3}{324^2}\] whatever that is

Answer 13

course amberjordan could be long gone by now...

Answer 14

oh hi. does this make sense?

Answer 15

whatever you get when you compute that number i wrote for h'

Answer 16

http://www.wolframalpha.com/input/?i=-500*3%2F324^2

Answer 17

well the problem is goofy, but i think the solution is correct