Question

Can someone help me with this please?
6+sqr24/2. the answer is 3+sqr6 but I am getting 3sqr12.
*sqr = radical sign

Answer 1

What you have is [6 + sqr(24)]/2. What you evaluated is 6 + sqr(24/2). Do you see the difference? Parentheses are important.
You have to be careful. First you need to simplify sqr(24) into 2sqr(6).
Then take your numerator 6 + 2 sqr(6) and factor out a 2: 2[3 + sqr(6)].
Now you can cancel the 2 you just factored out with the one in the denominator and get the answer 3 + sqr(6).

Answer 2

I don't understand why the sqr of 24 is implified to 2 times the sqr of 6.

Answer 3

simplified*

Answer 4

24 = 4 * 6
24 = 2^2 * 6 [because 4 = 2^2]

sqrt(24) = sqrt(2^2 * 6)

sqrt(24) = sqrt(2^2) * sqrt(6) [because sqrt(AB) = sqrt(A)*sqrt(B)

sqrt(24) = 2 * sqrt(6)

Is that what you needed?

The reason you need to simplify it first is that in order to simplify the entire expression, you will need to cancel the 2 in the denominator with a factor of 2 in the numerator. To do that, you have to have the entire numerator factored, not just part of it. For instance you can't simplify
(6x + 8)/2 to 3x + 8 or 6x + 4. You have to factor the 6x + 8 first.
(6x + 8)/2 = 2(3x + 4)/2 = 3x + 4.
Your problem is similar, but it is a bit more complicated because of the square root in it.

Answer 5

okay, thank you :)