Write an equation of the line that passes through (8, 3) and (4, 3).
Since the y coordinates are both equal to 3, the equation is y = 3 This is a horizontal line passing through 3 on the y-axis
Will you explain to me how to figure this out?
sure
Because I have several of these questions, and I want to understand how to do them
sure just post them to the left or you can ask here
Here is one that I dont understand -- Write the equation of the line that passes through (-4, 12) and (7, 23).
ok one sec
k
step 1 is to find the slope, how do we do that?
Don't you subtract 7 from -4 and 23 from 12?
yes and you divide those differences, which is the order we divide?
so what do you get when you do the subtractions?
When you subtract 7 - (-4) = 11 and 23-12= 11 ?
Good
Now you divide these differences, what value goes on top?
When you divide it you get 1
actually in this case, it doesn't matter, but it's important to know which value goes on top
yes, the result is 1
so the slope is 1
so m = 1 and we can plug that into y = mx+b to get y = 1x+b or just y = x+b
now we can use any of the two points to find the value of b So say we use (7, 23), this means that x = 7 and y = 23 So y = x+b becomes 23 = 7+b and solving for b gets us: b = 16 So the equation of the line is y = x+16
I think I have a good understanding, thank you very much
np
But hey, would you solve this problem the same way ? Write an equation in slope-intercept form of the line with an x-intercept of 6 and a y-intercept of 5.
when they say "x-intercept of 6 and a y-intercept of 5", they mean that this line goes through the points (6, 0) and (0,5)
so yes, you can use the same technique to solve this one
So i think I figured it out, but would my answer have 5/6 in it?
more like -5/6, but you probably lost a minus sign somewhere
that's the slope of course
I found my mistake(:
Thanks for being so helpful.
yw
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