Question

x^2/7 +x = -8/7 need to use quadratic formula :/

Answer 1

x^2 + 7x = -8
x^2 + 7x + 8 = 0

Answer 2

the x^2 is the numerator

Answer 3

\[\frac{1}{7}x^2 +x +8/7= 0\]

\[a = \frac{1}{7}, b = 1, c = \frac{8}{7}\]

In fact, get rid of those fractions
\[7\cdot(\frac{1}{7}x^2 +x +8/7)= 7\cdot0 \Rightarrow x^2 + 7x + 8 = 0\]
Now

\[a = 1 , b = 7 , c = 8 \]

\[x = \frac{-b \pm \sqrt{b^2-4ac}}{2a}\]

Answer 4

\[\frac{-7 \pm \sqrt{49-4(8)}}{2}\]
x =
\[\frac{-7 \pm \sqrt{17}}{2}\]

Answer 5

How do i get rid of the fractions? thanks :)