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Find the number c that satisfies the conclusion of the Mean Value Theorem. F(x)=x^3+x-8 [0,2]
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solve\[\frac{F(2)-F(0)}{2-0}=F'(c)\] for c
-8-2/-2
=5
so now i find the derivative of the equation and put =5?
5 is correct but you seemed to put it in backwards from what i wrote. yes...set the derivative of F equal to 5 and solve
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is the derivative is 3x^2+1 ?
yes
i dont know what to do from there
solve \(3x^2+1=5\)
\[2/\sqrt{3}\] !!! thank you
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