Question

Solve:

Answer 1

\[(x+3)^{2} + 2x = -3\]

Answer 2

itll be -2

Answer 3

we can expand the ( )'s
\[(x+3) (x+3) + 2x = -3\]then foil out the ( )'s\[x^2 + 6x + 9 + 2x = -3\]\[x^2 + 8x + 9 = -3\]add 3 to each side so our quadratic is equal to 0\[x^2 +8x + 12 = 0\]factor\[(x + 6) (x+ 2)\]\[x=-6\] and \[x= -2\]

Answer 4

Thank you...I calculated the parenthesis first and it screwed everything up. Thanks!