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Find all z in C which satisfy z conjugate = z^2
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Note C=Complex (x+iy)
0 works 1 works i don't think anything else works. \[(a+bi)^2=a^2-b^2+(2ab)i\] so this would mean you would have to solve \[a=a^2-b^2\] and \[b=2ab\]
sorry it is \[\overline{z }= z^2\] so it would be \[a=a^2-b^2\]and \[-b=2ab\] but the outcome is still the same
i got a=-1/2 and b=\[\sqrt{3}/2\]
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