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Simplify the expression sin(pi+x) + sin(pi - x)
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sin(x+ip)+sin(-x+ip)
is it?
NO , the answer is zero
\[\sin(x+\pi)=\sin(x)\cos(\pi)+\sin(\pi)\cos(x)=\sin(x)(-1)+0\cos(x)=-\sin(x)\] \[\sin(\pi-x)=\sin(\pi)\cos(x)-\sin(x)\cos(\pi)=0\cos(x)-\sin(x)(-1)=\sin(x)\]
what is -sin(x)+sin(x) ?
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of course you don't have to do all this but you can
sine is periodic with period \[2\pi\] and \[x+\pi\] \[-x+\pi\] are \[2\pi\] units apart. therefore the function is the same at both those points, and so the difference is zero
sorryy :(
yes its -sin(x)+sin(x)
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