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Mathematics 7 Online
OpenStudy (anonymous):

Simplify the expression sin(pi+x) + sin(pi - x)

OpenStudy (anonymous):

sin(x+ip)+sin(-x+ip)

OpenStudy (anonymous):

is it?

OpenStudy (anonymous):

NO , the answer is zero

myininaya (myininaya):

\[\sin(x+\pi)=\sin(x)\cos(\pi)+\sin(\pi)\cos(x)=\sin(x)(-1)+0\cos(x)=-\sin(x)\] \[\sin(\pi-x)=\sin(\pi)\cos(x)-\sin(x)\cos(\pi)=0\cos(x)-\sin(x)(-1)=\sin(x)\]

myininaya (myininaya):

what is -sin(x)+sin(x) ?

myininaya (myininaya):

of course you don't have to do all this but you can

OpenStudy (anonymous):

sine is periodic with period \[2\pi\] and \[x+\pi\] \[-x+\pi\] are \[2\pi\] units apart. therefore the function is the same at both those points, and so the difference is zero

OpenStudy (anonymous):

sorryy :(

OpenStudy (anonymous):

yes its -sin(x)+sin(x)

myininaya (myininaya):

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