Question

use basic identites to simply expression
cot usinu

Answer 1

plz explain detail

Answer 2

use addition

Answer 3

the answer is cos u

Answer 4

are you telling me \[\sin u \cos u=\cos u\]because that is not true

Answer 5

how basic do these identities have to be?
can we use \[\sin a \cos b={1\over2}[\sin(a+b)+\sin(a-b)]\]?

Answer 6

cot is cos/sin the two sin will be cancelled and the answer is cosu

Answer 7

oh I thought it was cos, not cot, my bad...
you seem to have the answer then, right?

Answer 8

can u plz answer onther one i dont know that

Answer 9

sure

Answer 10

1-cos2 x/sin x

Answer 11

\[{1-\cos^2x \over \sin x}\]right?

Answer 12

ya

Answer 13

start with the most basic identity\[\sin^2x+\cos^2x=1\]solve this for \[1-\cos^2x=?\]and you should get you answer.

Answer 14

is that sin x

Answer 15

yup yup!

Answer 16

thanks

Answer 17

whan i cut sin2 ans sin i got 1-sinx

Answer 18

so the answer is 1- sinx or sinx

Answer 19

ok, let's see what happened...

Answer 20

\[\sin^2x+\cos^2x=1 \to \sin^2x=1-\cos^2x\]plugging this into your formula gives\[{1-\cos^2x\over \sin x}={\sin^2x \over \sin x}=\sin x\]not sure what you did there...

Answer 21

i got u thx