Question

1) In a graph of acceleration vs. 1/mass, how can you tell that Fnet is constant? 2) Why is it necessary to balance the frictional force acting on the system with a slight tilting of the track?

Answer 1

Net force = (mass) x (acceleration). Hence if the acceleration is constant given that mass is also constant, then the net force must also be constant.

Answer 2

oh, I see, can I also say that the slope doesn't change?

Answer 3

?

Answer 4

If the slope is zero at part of the graph, then the function is constant on that part, yes.

Answer 5

u mean if a point on the line is (0,0), then I can say that the slope is constant?

Answer 6

But that is NOT the same thing as saying the slope doesn't change. If you're graphing acceleration against time, acceleration is not changing only if the graph is flat.

If the graph is increasing with constant slope, then acceleration in increasing.

Answer 7

For example, it looks like from t = 2 to 3, the acceleration here is flat, slope = 0. Therefore it is not changing.

Answer 8

this is acceleration vs. 1/mass

Answer 9

question is, how can u tell that Fnet is constant in an acceleration vs. 1/mass graph?

Answer 10

I am graphing on the x-axis time and on the y-axis acceleration.

What are you graphing?

Answer 11

the graph is a diagonal line

Answer 12

x-axis is 1/mass, not time lol and y-axis is acceleration

Answer 13

http://www.nstic.net.ph/text%20files/bb_teachers%20manual/09%20Newton's%20Second%20Law%20(TM).pdf pg 4

Answer 14

2nd graph

Answer 15

In which case, if F = constant = c, then as
F = ma and
x = 1/mass and y = a,
then
F = y/x = c => y = cx.

So yes, in that case, F = constant if the graph is a straight line passing through the origin.

Answer 16

wait, what else can I say besides: the graph is a straight line passing through the origin

Answer 17

can u say anything about acceleration, 1/mass, slope?

Answer 18

?

Answer 19

The slope of the graph is the force, F. As F = c and y = cx = Fx

Answer 20

so basically I can say that the slope is constant right?

Answer 21

This is a slightly bizarre way of thinking about this.

Provided F is constant, yes.

Answer 22

how about acceleration and 1/mass

Answer 23

can I say both are constant?

Answer 24

F = ma.

Absolutely no, they are not constant. That's what you are varying in this experiment.

Answer 25

oh, so I can only say 2 things: The graph is a straight line passing through the origin, and the slope is constant. In this case, the net force is equal to the slope. ?

Answer 26

yes.

Answer 27

Are you a teacher?

Answer 28

no, student

Answer 29

ur a teacher?

Answer 30

One time University Lecturer, yes.

Answer 31

nice :)

Answer 32

ok. I've got other fish to fry. Good luck.

Answer 33

Last question
: Why is it necessary to balance the frictional force acting on the system with a slight tilting of the track?

Answer 34

that's it after this one

Answer 35

a cart was rolling on a track

Answer 36

???