1. Suppose a coin is dropped from the top of the Empire State building in New York, which is 1, 454 feet tall. The position function for free-falling objects is: s(t) = −16t^2 + v0t + s0.

Determine the average velocity of the coin on the interval [1, 3].

Question

1.	Suppose a coin is dropped from the top of the Empire State building in New York, which is 1, 454 feet tall. The position function for free-falling objects is: s(t) = −16t^2 + v0t + s0.

Determine the average velocity of the coin on the interval [1, 3].

anonymous · Answer

The velocity function will be the derivative of the position function with respect to time.
So, v(t) = s'(t) = (2)*(-16)t. The initial velocity and position are both constants, so they will be eliminated from the derivative.

anonymous · Answer

To find the average velocity, you can take the value of the velocity function at the first point on the interval, add it to the velocity function valued at the end of the interval, and then divide by the length of the interval. So, the average velocity would be:
[v(1) + v(3)]/[3-1]

anonymous · Answer

What do you mean by v(1) and v(3)?