A ball is thrown in the air. After t seconds, the ball is at an altitude of h(t) = 12-3(t-2)^2 feet above the ground. what is the highest altitude above the ground that the ball will reach?

Question

mertsj · Answer

That is the equation of a parabola.  It's vertex is (2,12).  So 12 is the highest it will reach.

anonymous · Answer

if you rewrite the equation like this it might be easier y=-3(t-2)^2+12

anonymous · Answer

the vertex is either the highest or lowest point meaning th elocal max or min

anonymous · Answer

the equation y=a(x-s)+t
s is the x value of the vertex and t is the y value of the vertex

anonymous · Answer

we need to find out the y value sincethe y axis represents height/altitude