Question

HELP!!! PLEASE!!!

Caluclate how many grams of solid Mg(NO3)2 and Sr(NO3)2 to dissolve in water to make your solutions. Specifically,write out the calculations to prepare 100.0ml of 0.1000M Mg(NO3)2 and 100.0 ml of 0.1000M Sr(NO3)2. --The Mg(NO3)2 supplied comes in the form of Mg(NO3)2 6H2O, use the formula weight 256.4 grams per mole in the calculation for Mg(NO3)2.

Answer 1

(1) 0.1000M Mg(NO3)2 x 148.325gMg(NO3)2(divided by) 1MoleMg(NO3)2= 14.83gMg(NO3)2

Answer 2

That's for the Mg(NO3)2 part... I assume that's correct :)... now for the Sr(NO3)2 part:

Answer 3

hope you understand how to write it out in mathematical form :)

Answer 4

yes I do..Thank you so much...i am understand too

Answer 5

is this a mole or molarity question?

Answer 6

i am pretty sure it is molarity.

Answer 7

\[100.0 moles Sr(NO _{3})_{2}\times 211.64gSr(NO _{3})_{2}\div1mole Sr(NO _{3})_{2}=21144g Sr(NO _{3)_{_{2}}} \]

Answer 8

well, then that is not this correct answer... that's if you wanted to calculate moles
SORRY

Answer 9

HERE IS AN EXAMPLE OF HOW TO CALCULATE THE NUMBER OF GRAMS:
Set up general equation:
x M =y moles (divide by)z L

Substitute known values:
1.20 M =y moles/0.400 L

Solve for moles:
y moles =1.20 M x 0.400 L = 0.480 moles

Change to grams:
0.480 mole x 58.5 g/mole = 28.1 g

Answer 10

do you understand how to do the calculations? The reason I can't go through the whole process is because I am studying for an exam... but let me know if you understand or not .. Okay?

Answer 11

Oh sorry i should have messaged earlier...yes i understand thank you soooo much!!!!

Answer 12

You're welcome... I'm happy I could be of help... :)... Good luck :)

Answer 13

Good job Allison. Good luck on the exam