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OpenStudy (anonymous):
and x^3+9x^2+22x
OpenStudy (anonymous):
can you factor out anything here?
OpenStudy (anonymous):
x?
OpenStudy (anonymous):
correct, also if you are solving for the roots of an EQUATION i suggest you augment =0 to your equations.
OpenStudy (anonymous):
but it wants i to be in the factored form, in complex, how do i do that
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OpenStudy (anonymous):
what do you get if you factor out a zero?
OpenStudy (anonymous):
im confused
OpenStudy (anonymous):
lol i meant factor out an x
OpenStudy (anonymous):
whats your equation?
OpenStudy (anonymous):
x^3-6x^2+25x which would be x(x^2-6x+25)
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OpenStudy (anonymous):
now factor the x^2-6x+25 part
OpenStudy (anonymous):
uhm how
OpenStudy (anonymous):
you could use the quadratic equation? \[\frac{-b \pm \sqrt{b^2 - (4ac)}}{2a}\]
OpenStudy (anonymous):
i got (6 plusorminus √-64) / 2 so how do i put that in parenthesis
OpenStudy (anonymous):
\[\frac{6}{2} \pm \frac{\sqrt{-64}}{2}\] can you simplify this?
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OpenStudy (anonymous):
3plusorminus √-64/2?
OpenStudy (anonymous):
yes now can you simplify \[\frac{\sqrt{(-64)}}{2} \] what is -64 ? 64 times what?
OpenStudy (anonymous):
-1?
OpenStudy (anonymous):
-i?
OpenStudy (anonymous):
-1 is correct so it looks like this: \[\sqrt{(64)\times(-1)}\] and you were asking about complex numbers well do you know the definition of i and can you apply it here?
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OpenStudy (anonymous):
this is the same as \[\sqrt{64} \times \sqrt{-1} \]
OpenStudy (anonymous):
so how would it be?
OpenStudy (anonymous):
well what is the square root of 64?
OpenStudy (anonymous):
oh 8
OpenStudy (anonymous):
also what is the square root of -1?
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OpenStudy (anonymous):
and whats \[\frac{8}{2}\]
OpenStudy (anonymous):
4
OpenStudy (anonymous):
ok write out what you have reduced it to thus far?
OpenStudy (anonymous):
3plusorminus√-8
OpenStudy (anonymous):
\[3\pm \sqrt{-1}\times 8\] this is what you got, so how to we take care of the \[\sqrt{-1}\]
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OpenStudy (anonymous):
not sure
OpenStudy (anonymous):
google it, you will be surprised!
OpenStudy (anonymous):
i?
OpenStudy (anonymous):
w00t YES ISN'T THAT EXCITING!
OpenStudy (anonymous):
so whats the final solution?
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OpenStudy (anonymous):
3plusorminusi√8?
OpenStudy (anonymous):
why do you keep putting \[\sqrt{8}\] in there?
OpenStudy (anonymous):
idk
OpenStudy (anonymous):
we said that \[\sqrt{64}\] was 8 right? So therefore its just 8 but then its \[\frac{8}{2}\] was it not?
OpenStudy (anonymous):
so 8i?
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OpenStudy (anonymous):
check again its not 8, write out the entire simplified solution for me pelase!
OpenStudy (anonymous):
--_____---
OpenStudy (anonymous):
you are almost there dont give up go back and look at the conversation!!!!!
OpenStudy (anonymous):
i fel like giving up
OpenStudy (anonymous):
well dont you are almost there!!!!! keep trying!
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