Mathematics
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OpenStudy (anonymous):
Suppose the magnitude of C=6 and the magnitude of D=4, and l C x D l= 12. Find C dot D?
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OpenStudy (anonymous):
are these vectors or just regular numbers?
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
the answer is 12 root 3, but I'm really not sure how to start the problem
OpenStudy (anonymous):
it's been some time since I've done vectors lol
give me a minute
OpenStudy (anonymous):
what is l C x D l exactly?
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OpenStudy (anonymous):
cross product?
OpenStudy (anonymous):
magnitude of the cross product of C and D?
OpenStudy (anonymous):
alright, busting out my old notes for this lol
you know that |C x D| = |C||D|sin(theta) right?
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
you know all the values there except for theta so you can solve for that
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OpenStudy (anonymous):
is C dot D= lCllDl cos(theta) also?
OpenStudy (anonymous):
yes, so all you need is the angle
OpenStudy (anonymous):
how do I find the angle?
OpenStudy (anonymous):
|C x D| = |C||D|sin(theta)
(12) = (6)(4)sin(theta)
(12) = (24)sin(theta)
12/24 = sin(theta)
1/2 = sin(theta)
OpenStudy (anonymous):
so I plugged in the numbers and got 60 degrees
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OpenStudy (anonymous):
oh! I got it!
OpenStudy (anonymous):
6*4sin(60)= 12 rt 3. phew
OpenStudy (anonymous):
thank you!!
OpenStudy (anonymous):
yeah no problem, good job!