Mathematics
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OpenStudy (anonymous):
Factor Completely, 3y^2 +7y + 4
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OpenStudy (anonymous):
(3y+4)(y+1)
OpenStudy (anonymous):
(3y + 4) (y + 1)
OpenStudy (anonymous):
do u understand y this is the answe?
OpenStudy (anonymous):
no i dont i cant figure out how to do these
OpenStudy (anonymous):
ok so there is a method
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OpenStudy (anonymous):
First see if you can factor but here you can't so we go to the second step
OpenStudy (anonymous):
ax^2+bx+c=y
OpenStudy (anonymous):
Multiply a*c
3*4=12
OpenStudy (anonymous):
so what number when you multiply it equals 12 but when you add it equals b-7?
OpenStudy (anonymous):
So u tell me the answer
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OpenStudy (anonymous):
What two numbers when you multiply them equals 12 and when you add them equals 7
OpenStudy (anonymous):
4 and 3
OpenStudy (anonymous):
yup
OpenStudy (anonymous):
so now what u wld do is divide the bx into two
7x becomes 3x+4x
OpenStudy (anonymous):
3x+4x=7x so it isn't a big deal to separate them
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OpenStudy (anonymous):
So we rewrite the answer question as:
3y^2+3y+4y+4
OpenStudy (anonymous):
Now we separate the equations into two and i cant explain you this steo since i dont get the logic behind it myself
OpenStudy (anonymous):
(3y^2+3y)(4y+4)
OpenStudy (anonymous):
Now factor each bracket
3y(y+1)+4(y+1)
OpenStudy (anonymous):
did you get he steps so far?
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OpenStudy (anonymous):
oh u are long gone so i will ust finish off what i was saying
OpenStudy (anonymous):
no im still her just trying to put it all together
OpenStudy (anonymous):
then since 3y and 4 are multiplied by (y+1) we can join them together so
(3y+4)(y+1)
OpenStudy (anonymous):
ok basically you gotta memorize the steps and then it becomes second nature