((x+1)(2x+1)^2)/((x^2-1)(x-3))
find zeros, all asymptotes, holes, end behavior, vertical asymptote behavior, multiplicity

Question

hero · Answer

Have you tried graphing the function on a graphing calc yet?

hero · Answer

Which parts don't you understand?

curry · Answer

the asympotote

curry · Answer

behavior

hero · Answer

There's a general method for finding vertical asymptotes of functions. The vertical asymptote usually occurs where x would make the denominator equal zero. So set the denominator equal to zero, then solve for x.

anonymous · Answer

hero u r such a teacher!!!

hero · Answer

Why does that surprise you?

curry · Answer

dude hero cme on u know i kno that i m taking about asymptotic behavior

curry · Answer

not finding it

hero · Answer

What about the asymptotic behavior?

curry · Answer

wat is it

anonymous · Answer

i think i surprised you yesterday!!!

anonymous · Answer

where the asymptotes are!

curry · Answer

like whatsthge answer for this problem

anonymous · Answer

oh asymptotes and the behavior are diff things

curry · Answer

using limit notaition and saying how the graph is approaching from the complex roots and inifinity

hero · Answer

as x approaches the vertical asymptote from the negative side, the graph approaches positive infinity. As x approaches the vertical asymptote from the postive side, the graph also approaches positive infinity. Is that what you're talking about?

anonymous · Answer

did u sign up to ottawa yet?

curry · Answer

actually hero ur right but you are wroong there is 2 asymptotes which means there are 4 limit notaions

hero · Answer

Yes, I applied

anonymous · Answer

oh so what classes did u sign up 4?

hero · Answer

I'm in the process of sending over my transcripts. I'll take whatever classes you're taking that way we can study together or be study buddies.

anonymous · Answer

oh we r buddies?

hero · Answer

Not yet

hero · Answer

Well Curry, the point was for you to "get it". I think I've provided you with the information you need.

curry · Answer

pshh hero u dont know it do u
i known u for too long

anonymous · Answer

what do u mean?

curry · Answer

ive known hero i know what he says when he is in a sticky spot

anonymous · Answer

u mean that he didnt want to say that he doesn't know the answer?

anonymous · Answer

ya cuz then he wont be the hero nemore

curry · Answer

yep

hero · Answer

I already explained to you how to find the asymptotes and how to express the behavior.

hero · Answer

it was a general explanation

anonymous · Answer

curry there is no reason to put down hero he was just trying to help u

hero · Answer

rld, I can handle myself. I don't need you to speak up for me :P

anonymous · Answer

well i want to

hero · Answer

Okay then :D

curry · Answer

thats the behavior approaching the asymptotes there is 2 middle behaviors on the graph it looks different but the problem it self is giving diffrent answer and rld me and hero are best friends

anonymous · Answer

oh ya?????

curry · Answer

its all good he has the right to say it to me

anonymous · Answer

hero and i are not friends

hero · Answer

That's what she keeps claiming

anonymous · Answer

i thought i proved it already