Find the domain of a function: G(x)=8/8-5x
all real numbers not equal to 8/5
You cannot divide by zero, so 8-5x can't be zero If it were, then 8-5x = 0 means that x = 8/5 So when x = 8/5, the denominator 8-5x is zero So this means that we must remove this value from the domain. So the domain is the set of all real numbers except x cannot equal 8/5
x is a real number and x\[\neq 0\]
close, more like x is a real number and \[\Large x \neq \frac{8}{5}\]
oh ok...i got confused with the equal sign with that slash through it...thank you Jim
np
question. so with this i would have the open signs on each end correct ( )?
are you referring to using interval notation?
yes
yes, you would use parenthesis and the domain in interval notation is \[\Large \left(-\infty,\frac{8}{5}\right)\cup\left(\frac{8}{5},\infty\right)\]
thats is what i got, however, i am a little confused on one part..i have to choose the right domain and this is what i have. \[ a. [x \ge8/5], b. {x \neq8}, c. [x \neq8/5], or d. {x \neq0}\]
it's choice C
c would be my answer correct?
yep, you nailed it
basically x can be any number but 8/5
thats what i thought..i did have my answer, just confused sometime with those signs { } and [ ].
thanks bunches again. aloha
well {} refers to sets
and [] is used in interval notation
C is the closest even though the [] should be {}
oh ok, i will write that for my notes, i am new to this algebra1, never taken algebra ever..TY
np
right, thats what i got :)
it should be \[\{x \neq \frac{8}{5} \}\]
sry the symbol didn't show up, but you got the idea
i wonder why it would have [ ] instead of { }?
yes.
typo perhaps
haha, i get those at times
lol that's why it's important to not always trust the computer
exactly
i got one more problem, its a word problem..i will post a new one, its been mind boggling for me
k
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