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hero (hero):
Let me guess, you want to understand the asymptote behavior
OpenStudy (curry):
where is the function negative and where is it posotice
OpenStudy (curry):
positive?
OpenStudy (curry):
and where is function is undefined
hero (hero):
The function is positive everywhere it is above the x axis and negative everywhere it goes below the x axis. It is undefined anywhere the denominator equal zero
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OpenStudy (curry):
i know that hero u keep stating something i already know. I just dont get this problem
hero (hero):
Graph it
OpenStudy (anonymous):
find the second derivative and set it equal to 0 to find the critical points. and then test the concavity
OpenStudy (curry):
i got postive [5,infinity]
negative (4,5]
OpenStudy (curry):
but is 5 soppused to be closed for the positive or negative or both like i have it or neither
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OpenStudy (anonymous):
5 is 0, right?
OpenStudy (curry):
but is 5 soppused to be closed for the positive or negative or both like i have it or neither
OpenStudy (curry):
ye
OpenStudy (anonymous):
It is precalc , or calc
OpenStudy (anonymous):
i think 0 is neither
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