((x+1)(x-5)(x^3-3))/(sqrt(x-4))
Let me guess, you want to understand the asymptote behavior
where is the function negative and where is it posotice
positive?
and where is function is undefined
The function is positive everywhere it is above the x axis and negative everywhere it goes below the x axis. It is undefined anywhere the denominator equal zero
i know that hero u keep stating something i already know. I just dont get this problem
Graph it
find the second derivative and set it equal to 0 to find the critical points. and then test the concavity
i got postive [5,infinity] negative (4,5]
but is 5 soppused to be closed for the positive or negative or both like i have it or neither
5 is 0, right?
but is 5 soppused to be closed for the positive or negative or both like i have it or neither
ye
It is precalc , or calc
i think 0 is neither
so it would be open both times
?
open i think
Join our real-time social learning platform and learn together with your friends!