Question

Please help me prove this trig identity....

(secx - cosecx)/(tanx - cotx) = (tanx - cotx) /(secx - cosecx)

Answer 1

i would write both sides in terms of sin(x) and cos(x) and clear the compound fractions

Answer 2

and then you might have to use some other identities

Answer 3

break up the LHS into \[\frac{sec x}{tan x - cot x} + \frac{-csc x}{tan x - cot x} \]

Answer 4

Oh....I'll try it that way then but Im not sure if I can reach the answer still.... And how can I change them to cos and sin? they are not squared :(

Answer 5

my advice would be to multiply by one using \[\frac{sinx}{sinx} \]

Answer 6

he means turn sec x into \[\frac{1}{cos x} \] etc...

Answer 7

for multiplying by one like i said above, dont use sin...use something that will reduce everything...

Answer 8

hmmm

Answer 9

i tried turning tan into sin/cos and cot into cis/sin and then I got all tans and cos's too

Answer 10

try taking everything in terms of cos and sin and then simplifying as much as you can. Don't leave any sec, csc, tan or cot