Use Cramer's rule to solve the system. -4x + 3y + 3z = 12 -2y - 2z = -16 3x - 3z = -12
\[\left[\begin{matrix}-4 & 3 & 3 & 12 \\ 0 & -2 & -2 & -16 \\ 3 & 0 & -3 & -12 \end{matrix}\right]\] so matrix looks like this, do you know the computation for cramers rule?
yes
but with two, so how would it be with 3?
\[x1 = \frac{\det(\left[\begin{matrix} 12 & 3 & 3 \\ -16 & -2 & -2 \\ -12 & 0 & -3 \end{matrix}\right])}{\det(\left[\begin{matrix} -4 & 3 & 3 \\ 0 & -2 & -2 \\ 3 & 0 & -3 \end{matrix}\right])}\] would be how to solve for x1 and you need to take the det of a 3x3, do you have a graphing calculator?
No
then this is going to suck!!!!
if i find a graphing calculator just plug in the numbers right?
yes and then solve each matrix's determinant and divide them and get x1
ok, thanks
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