((x+1)|x-5|)/sqrt(x-4)=>0
\[\frac{(x + 1) |x-5|}{\sqrt{x-4}} \ge 0\] -------------------------------|----------------------------------------------------------------------- -1 Hmm |x - 5| is always positive and so is sqrt{x - 4} for x greater than 4 Hence this function is always positive for x >4 if we chose less numbers less than 4 we will have a imaginary number in the denominator not valid over real numbers
The whole function R to R is only valid for x > 4 and for x >4 the function is always positive
ty that helped so much
are u going to be on for a while
No Problem
Yeah ask me anything but asymptotes, they don't teach it here (In India)
i can if u want
um look at this link it will take me too long for me explain
Okay! :D
Thanks!
an asymptote is a line in the graph where the equation will never cross
Hmm Interesting
Hmm Nice the Link is good, I gotta practice asymptotes now
Thanks Again, I will be on for an hour or so; You can Ping Me(Kick Me from Hacking Group) If help's needed
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