Can you show me by steps how to solve this problem . ? y/3 + 8y/4 - 3/6= y + 7/2
bring all the vaiables on one side \[\frac{y}{3}+\frac{8y}{4}-y = \frac{7}{2}+\frac{3}{6}\]
\[\frac{y}{3}+2y-y=\frac{7}{2}+\frac{3}{6}\]
\[\frac{y}{3}+y=\frac{7}{2}+\frac{3}{6}\]
now u need a common denominator\[\frac{y}{3} +(y \times \frac{3}{3}) = \frac{7}{2} +\frac{1}{2}\]
\[\frac{y}{3} + \frac{3y}{3} = \frac{8}{2}\]
\[\frac{4y}{3}=4\]
\[\cancel{3} \times \frac{4y}{\cancel{3}} = 4 \times 3\]
\[4y=12\]\[y=\frac{12}{4} = 3\]
thank youu !!
your welcome
ii may need more help tho . ! :D
hehe :D ill be glad to help
well , my daughter is taking a 25 question test ; maybe we can review her work ?
write and solve the algebraic inequality ; -5 and a number is at least 40.
-40 *
this problem has answer choices , && -35 isn't on there . It's a little hard too explain , shall I just ask another question . ?
|dw:1322826407011:dw| Here is the next problem.
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