How do i plot r^2=-sin(theta)

Question

anonymous · Answer

find table of values for r with corresponding value of theta.........
plot r in y axis and theta in x axis

anonymous · Answer

but if i take the square root of both sides, i can have that negative sin under the square root can i

anonymous · Answer

ya you cant have negative sign under root........for the values of theta greater than 180 and less than 360 , you will have negative values of sintheta so negative and negative makes positive..........

anonymous · Answer

What about, how do i test for symmetry

anonymous · Answer

what does test for symmetry mean exactly, i am not getting it....... you told previously that you need to plot on the graph

anonymous · Answer

No can you help me with this, i am just learning how to do polar equations if you could hsow me how to do this one it would greatly help

anonymous · Answer

Well i know r=a is a line, would r^2 be a parabola

anonymous · Answer

2bornoto2b, you are quite a teacher

anonymous · Answer

yes ma'am

anonymous · Answer

yeah, i did thank you, But in my book the graph is of two circles

anonymous · Answer

2bornoto2b, what software you use?

anonymous · Answer

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anonymous · Answer

2bornto2b, why we need to slipt the graph............

anonymous · Answer

Something like that, but the two circle are symmetric

2bornot2b · Answer

Oh dear, then its a polar equation. Its not a coordinate one.

anonymous · Answer

yeah, its a polar equation, sorry i forget to mention

anonymous · Answer

oh.......but he has not mentioned that

2bornot2b · Answer

Actually I guessed it because he used to variables, and I changed them to one, silently

2bornot2b · Answer

*two not to

anonymous · Answer

oh! but what about the diagram he has shown

2bornot2b · Answer

I don't have any idea about your level of education. But still I guess you know these
x=rcos@, y=rsin@
r=(x^2+y^2)^0.5
Do you know these?

anonymous · Answer

yes

2bornot2b · Answer

Now do you realize that the equation in coordinate form is 
(x^2+y^2)^(3/2)=-y

anonymous · Answer

I take that back

anonymous · Answer

What? how i that possible

anonymous · Answer

is*

anonymous · Answer

I understand thje x^2+y^2 but how come it is ^3/2

2bornot2b · Answer

Use pen and paper, and use the relations
x=rcos@, y=rsin@
r=(x^2+y^2)^0.5

anonymous · Answer

yea, i get that one, but what about the ^(3/2) where is that coming from

2bornot2b · Answer

1/2+1

anonymous · Answer

why are you adding a one

2bornot2b · Answer

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