Mathematics
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OpenStudy (anonymous):
Okay, How do I know if the Integral, limits are 6 and infinity, of 1/(x+4)^(1/5) converges or diverges?
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OpenStudy (amistre64):
if the integral goes off to iinfinity; its diverging
OpenStudy (anonymous):
So do I integrate it first, then plug in infinity for x then subtract after I plig in 6 for the bottom limit?
OpenStudy (amistre64):
integrate it first, yes
OpenStudy (anonymous):
so I get 3/(5(x-3)^(5/3)?
OpenStudy (amistre64):
i get 4/5 .....
-1/5 + 5/5 = 4/5
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OpenStudy (anonymous):
oh woops
OpenStudy (amistre64):
\[\int(x+4)^{-1/5}dx=\frac{5}{4}(x+5)^{4/5}\]
OpenStudy (amistre64):
the 6 is useless in this regards since it adds no real value;
and at infinity we just get infinity
OpenStudy (anonymous):
Okay, so when I plug in infinity and subtract the six plugged in, what do I get? This is where i get lost usually
OpenStudy (anonymous):
okay, so 1/infinity would be congerging on zero?
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OpenStudy (amistre64):
forget the clutter;
(infinity)^4/5 i believe is just infinity
OpenStudy (amistre64):
1/large goes to zero, yes
OpenStudy (anonymous):
but its under 1, so it would be getting smaller
OpenStudy (amistre64):
1/100000 of a piece of pie is a very tiny piece
OpenStudy (amistre64):
this isnt under 1
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OpenStudy (anonymous):
under 5 sorry
OpenStudy (amistre64):
\[5\sqrt[5]{(\infty+4)^4} \over 4\]
OpenStudy (anonymous):
ohhhh
OpenStudy (anonymous):
so its diverging
OpenStudy (anonymous):
gotcha thanks alot
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OpenStudy (amistre64):
:) good luck
OpenStudy (anonymous):
hey