Question

find the domain

f(x)=log(x^2+4x+4)

Answer 1

You can find the log of any number provided it is >0. Therefore, x^2+4x+4 > 0 for this question. Then just treat it as a normal equation. Factoring gives you (x+2)^2 >0, meaning x > -2.

Domain: {x E R | x > -2}

Answer 2

oh ok thank you!

Answer 3

Not entierly true...

Answer 4

If you try -3 you get ln(1) which is 0

Answer 5

the domain can't be -2 though... so i think the domain is -2 < x <-3

Answer 6

\((x+2)^2 >0\Rightarrow x\ne-2\)

Answer 7

You're right alifetouni my bad. The domain is actually x =/ (not equal) -2. Since you're squaring the (x+2) factor, any number you sub in will be positive and thus >0, except -2.

Domain: {x E R | x =/ -2}