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OpenStudy (anonymous):
\[\int\limits_{0}^{1}x + \sqrt{1-x^2}dx\]
OpenStudy (anonymous):
Any ideas??
OpenStudy (anonymous):
Its given an area under curve y = x+root(1−x2)
OpenStudy (anonymous):
more precisely, area under curve, line x=1, x=0 and y=0
OpenStudy (anonymous):
Ok
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OpenStudy (anonymous):
Sooo what do i do?? Im still confused
OpenStudy (anonymous):
you integrate first than find the value of inegration when x=0 and when x=1....subtract answer from x=1 to x=0..so thats the area
OpenStudy (mr.math):
The first term represents the area of a triangle with base and height equal to 1 unit length. Its area is equal to 1/2(1)(1)=1/2.
OpenStudy (mr.math):
The second term represents the part in the first quadrant of a circle centered at the origin and with radius one. Its area is 1/4*pi*1=pi/4. So the value of the given integration is 1/2+pi/4=(2+pi)/4.
OpenStudy (anonymous):
^^ You are a life saver!! Thank you sooo much!!
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