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Mathematics 16 Online
OpenStudy (anonymous):

Evaluate by interpreting it in terms of areas.

OpenStudy (anonymous):

\[\int\limits_{0}^{1}x + \sqrt{1-x^2}dx\]

OpenStudy (anonymous):

Any ideas??

OpenStudy (anonymous):

Its given an area under curve y = x+root(1−x2)

OpenStudy (anonymous):

more precisely, area under curve, line x=1, x=0 and y=0

OpenStudy (anonymous):

Ok

OpenStudy (anonymous):

Sooo what do i do?? Im still confused

OpenStudy (anonymous):

you integrate first than find the value of inegration when x=0 and when x=1....subtract answer from x=1 to x=0..so thats the area

OpenStudy (mr.math):

The first term represents the area of a triangle with base and height equal to 1 unit length. Its area is equal to 1/2(1)(1)=1/2.

OpenStudy (mr.math):

The second term represents the part in the first quadrant of a circle centered at the origin and with radius one. Its area is 1/4*pi*1=pi/4. So the value of the given integration is 1/2+pi/4=(2+pi)/4.

OpenStudy (anonymous):

^^ You are a life saver!! Thank you sooo much!!

OpenStudy (mr.math):

Glad to help!

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