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find volume of the tetrahedron formed by x+y+z=1 using double integrals.
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\[\int\limits_{0}^{1}\int\limits_{0}^{1-x}(1-x-y)dydx\]
i get 1/3 can u confm
1/6
I don't know how u get 1/6
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did you evaluate the dx integral at 0?
do you see where you made your mistake?
no
\[\left.x-x^2+\frac{x^3}{3}+\frac{(1-x)^3}{6}\right|_{0}^{1}\] \[=\left(1-1^2+\frac{1^3}{3}+\frac{(1-1)^3}{6}\right)-\left(0-0^2+\frac{0^3}{3}+\frac{(1-0)^3}{6}\right)\] \[=1-1+\frac{1}{3}+0-0+0-0-\frac{1}{6}=\frac{1}{3}-\frac{1}{6}=\frac{1}{6}\]
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