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Physics 18 Online
OpenStudy (anonymous):

(Newton's Law of Motion) A 400 kg load of bricks on a 50 kg pallet is raised with an acceleration of .40 m/s^2. (a) What is the tension in the supporting rope? (b) The empty pallet is lowered with a downward acceleration of 0.60 m/s^2. What is the tension in the rope now?

OpenStudy (anonymous):

f=ma f=450X.40 b>50x0.60

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