Question

3) Find an equation of the tangent line to the graph of y = 3x2 – ex + 2 at (0,1)

Answer 1

\[y = 3x ^{2} – e ^{x} + 2\]

Answer 2

ghass, thanks soo mch for replying to the translating probelm! you are a genius!

Answer 3

Do you recall the geometrical meaning of the derivative?

Answer 4

yes

Answer 5

first differentiate the equation,f y = 3x^2 – e^x + 2
you'll get the slope of the tangent
y'=6x-e^x
y']at (x=0)=-1
so the slope of the line =-1
then the equation is => y-1=-1(x-0)
=> y-1 =-x

Answer 6

and so , x+y-1=0 is the tangent

Answer 7

thanks!!