List all the asymptotes for the following.
a) y=2/(x^2-1)
y=2/((x+1)(x-1))
Vertical Asymptote: X = 1, X = -1
Horizontal Asymptote: None
Oblique Asymptote:
Missing Points:

Question

List all the asymptotes for the following.
a) y=2/(x^2-1) 
y=2/((x+1)(x-1))
Vertical Asymptote: X = 1, X = -1
Horizontal Asymptote: None
Oblique Asymptote: 
Missing Points:

anonymous · Answer

is there horizontal asymptote

anonymous · Answer

$$y = 2/(x ^{2}+1)$$

anonymous · Answer

I would say yes... :) Since the degree of denominator > nominator, you could ask yourself what happens if the limit of x->inf (+-). The function here would go to zero, and that would be the horzontal asymptote..

Hope this helps!

//Ali

anonymous · Answer

No oblique one..
You find the oblique one if the Nominator is 1 degree lager than the denominator.

anonymous · Answer

also isnt degree of numerator greater since x^2 -1 = 0

anonymous · Answer

With the degre you mean the degree of the variable asked for. So no the degree of the denominator here, is greater than the nominator. Has nothing to do with x^2-1=0.