(Newton's Law of Motion) A parachutist whose total mass is 100 kg is falling at 50 m/s when her parachute opens. Her speed drops to 7m/s in a vertical distance of 40 m. What total force did her harness have to withstand?

Question

ash2326 · Answer

v^2-u^2=2as
here v final velocity is 7m/s
u initial velocity is 50 m/s
s=40m
7^2-50^2=2a*40
49-2500=80a
80a=-2451
a=-30.6375m/s^2 (-ve because opposite to the motion)
Force on the harness=ma
=100*30.6375
3063.75 Newtons