Question

partial fractions

Answer 1

are annoying

Answer 2

\[\int\limits (x+1)/x^3-2x^2+x\]

Answer 3

x/x^3 + 1/x^3 - 2x^2 + x

Answer 4

1/x^2 + 1/x^3 - 2x^2 + x

Answer 5

x^-2 + x^-3 - 2x^2 + x

Answer 6

and integrate
(x^-1)/-1 + (x^-2)/-2-(2x^3)/3+(x^2)/2

Answer 7

-1/x-1/(2x^2)-2x^3/3+x^2/2

Answer 8

\[\frac{(x+1)}{x(x-1)^2}=\frac{A}{x} +\frac{B}{x-1}+\frac{C}{(x-1)^2}\]\[(x+1)=A(x-1)^2+Bx(x-1)+cx\]\[(x+1)=Ax^2-2Ax+A+Bx^2-Bx+Cx\]
\[A=1\]\[-2A-B+C=1\]\[A+B=0\]since A=1
1+B=0
B=-1
and -2A-B+C=1
-2(1)-(-1)+C=1
-2+1+C=1
C=2

Answer 9

\[\frac{x+1}{x(x-1)^2}= \frac{1}{x}-\frac{1}{x-1}+\frac{2}{(x-1)^2}\]

Answer 10

ok i see where i messed up at

Answer 11

how about using some parenthases in your problem >_>

Answer 12

There are different methods for solving partial fractions .. you should look at heavy side Partioning .. this gives answer real quick ;)