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Compute f(x)=2t(sin(t^2))dt from -1 to x
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t^2 = u use this :)
ok, thanks :) i was substituting sint^2 by mistake
is it cosx^2-cos1 or cos1-cosx^2?
\[2t*\sin t^2 dt\] \[t^2= u\] \[dt = \frac{dy}{2t}\] \[ \frac{2t}{2t}\sin u*du\]
-cos u - cos t^2 -cos x^2 + cos 2
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sorry cos 1 - cos x^2
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