Question

Consider the function f(x)=6x^3−45x^4,x>0.

Let F(x) be the antiderivative of f(x) with F(1)=0. Then F(x)=

Answer 1

sorry! its 6/x^3....

Answer 2

\[F'(x)=f(x)\]
\[ f(x)=6x^3−45x^4\]
\[F(x)=3x^4/2-9x^5+C\]
\[F(1)=3(1)^4/2-9(1)^5+C=0\]
\[C=15/2\]
\[F(x)=3x^4/2-9x^5+15/2\]

Answer 3

lol