Question

18t^2=-9t+5

Answer 1

\[18t ^{2}+9t-5=0\]

Answer 2

i got that and a=18,b=9,c=-5

Answer 3

help me :(

Answer 4

(3t-1)(6t+5)=0

Answer 5

how does it change if you use the quadratic equation

Answer 6

t = 1/3, t = -5/6

Answer 7

it doesnt change anything if you use the quadratic....it comes out to the same in the end

Answer 8

Firt we simplify
we make it look like this 18t^2 + 9t - 5= 0
Using Quadratic formula we have

x = (-b + sqrt(b^2 - 4ac))/2a
and x = (-b - sqrt(b^2 - 4ac))/2a

if we use at^2 + bt + c = 0
and compare with 18t^2 + 9t -5 =0
we get a= 18, b=9, c=-5
so, x = 0.333
and x=-0.833

Answer 9

18t^2=-9t+5

18t^2 + 9t - 5 = 0

a = 18
b = 9
c = -5

Insert those values in Quadratic equation. and u are done! :)

Answer 10

18t^2=-9t+5
18t^2+9t-5=0
18t^2+15t-6t-5 = 0
3t(6t+5)-1(6t+5)=0
(6t+5)(3t-1)=0
t = -5/6, 1/3