Question

Solve. 2x^2 – 3x + 6 = 0

Answer 1

complex solutions for this one
use
\[x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\]with
\[a=2,b=-3,c=6\]

Answer 2

get
\[x=\frac{3\pm\sqrt{-39}}{4}\]

Answer 3

Solve. x^2 + 4x – 4 = 0

Answer 4

I just tried solving this. But i got the wrong answer. Can you help me again?):

Answer 5

real solutions for this one

Answer 6

easiest to write
\[x^2+4x=4\]
\[(x+2)^2=4+2^2+8\]
\[x+2=\pm\sqrt{8}=\pm2\sqrt{2}\]
\[x=-2\pm2\sqrt{2}\]

Answer 7

typo there. second line should be
\[(x+2)^2=4+2^2=8\]

Answer 8

yes a typo!