Hero can u please help me with questions 28 and 30???
page?
HUH why is it empty?
Is it balnk by u too>
ok that is better. Sorry abt that
I found it on the first one you sent me. Did you graph this to see what it looked like?
Let me guess....no
no not at all
Okay, well let me graph it for you and send it to you
I am lazy
Hey u r so nice
but lie it is so annoying since it 1 2 3 and 4. i wld like it to be in radians
3 is like pi
I am supossed to be heading to bed in 3 minutes LOL
Just a sec
ok
That should give you a better idea of what is going on
ya ok i saw it
my answer though may be correct
It must be since i used my calc
Basically, when you take the integral you should get a positive value. You have two areas One area goes from 0 to 2.5 the other goes from 2.5 to 4 The area above the x-axis from 0 to 2.5 is greater than the area below the x-axis from 2.5 to 4 Therefore, the total area when added won't be that much. because you're subtracting one area from the other area.
so i got s/t like .8048960342
no
3.99 or approx 4
y not?
Because I will show you
Y show me :D
oops, nevermind
so am i correct?
and what does it mean to interpret in in erms of area?? I dont get that
Hero is here but not here at the same time
Yes, you're right. It's only .804
ok so what does it mean to interpret it in terms of area?
It means to measure the space between the x axis and the curve
I wish you had my calculator. That way you could see visually how it works
oh so the answer wld be this .804??
christmas i will find a good deal hopefully. My dad is already going bankrupt from me!!!
HERO where r u?
I will show you how to make sense of this.
I'm going to send you another picture
ok. It isnt area but just displacement no??
oh ya thanks :D
I'll show you exactly what it is. It' will be almost dummy proof
:D:D:D
Thanks
U r the best
x = 2.5 is where the function hits the x axis and also where y = 0 Take the integral of the function from 0 to 2.5 Then take the integral of the function from 2.5 to 4 The absolute value of their differences will be the total area under the curve of the function from 0 to 4
Does it make any sense yet?
so basically it is the change in placement
I hope i am not stressing you out but like it is the positive area minus the negative area which is change in placenent kind of
The area under the curve is essentially the combined area of the space under the curve that you see shaded in grey. Yes, it does INVOLVE subtracting the areas below the x-axis from those above the x-axis. But area simply means "region of space". I think that's what you should understand about it. You have a region of space under the curve of a function and that is what you are measuring.
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