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Mathematics 14 Online
OpenStudy (anonymous):

Hero can u please help me with questions 28 and 30???

hero (hero):

page?

OpenStudy (anonymous):

OpenStudy (anonymous):

HUH why is it empty?

OpenStudy (anonymous):

Is it balnk by u too>

OpenStudy (anonymous):

OpenStudy (anonymous):

ok that is better. Sorry abt that

hero (hero):

I found it on the first one you sent me. Did you graph this to see what it looked like?

hero (hero):

Let me guess....no

OpenStudy (anonymous):

no not at all

hero (hero):

Okay, well let me graph it for you and send it to you

OpenStudy (anonymous):

I am lazy

OpenStudy (anonymous):

Hey u r so nice

OpenStudy (anonymous):

but lie it is so annoying since it 1 2 3 and 4. i wld like it to be in radians

OpenStudy (anonymous):

3 is like pi

OpenStudy (anonymous):

I am supossed to be heading to bed in 3 minutes LOL

hero (hero):

Just a sec

OpenStudy (anonymous):

ok

hero (hero):

hero (hero):

That should give you a better idea of what is going on

OpenStudy (anonymous):

ya ok i saw it

OpenStudy (anonymous):

my answer though may be correct

OpenStudy (anonymous):

It must be since i used my calc

hero (hero):

Basically, when you take the integral you should get a positive value. You have two areas One area goes from 0 to 2.5 the other goes from 2.5 to 4 The area above the x-axis from 0 to 2.5 is greater than the area below the x-axis from 2.5 to 4 Therefore, the total area when added won't be that much. because you're subtracting one area from the other area.

OpenStudy (anonymous):

so i got s/t like .8048960342

hero (hero):

no

hero (hero):

3.99 or approx 4

OpenStudy (anonymous):

y not?

hero (hero):

Because I will show you

OpenStudy (anonymous):

Y show me :D

hero (hero):

oops, nevermind

OpenStudy (anonymous):

so am i correct?

OpenStudy (anonymous):

and what does it mean to interpret in in erms of area?? I dont get that

OpenStudy (anonymous):

Hero is here but not here at the same time

hero (hero):

Yes, you're right. It's only .804

OpenStudy (anonymous):

ok so what does it mean to interpret it in terms of area?

hero (hero):

It means to measure the space between the x axis and the curve

hero (hero):

I wish you had my calculator. That way you could see visually how it works

OpenStudy (anonymous):

oh so the answer wld be this .804??

OpenStudy (anonymous):

christmas i will find a good deal hopefully. My dad is already going bankrupt from me!!!

OpenStudy (anonymous):

HERO where r u?

hero (hero):

I will show you how to make sense of this.

hero (hero):

I'm going to send you another picture

OpenStudy (anonymous):

ok. It isnt area but just displacement no??

OpenStudy (anonymous):

oh ya thanks :D

hero (hero):

I'll show you exactly what it is. It' will be almost dummy proof

OpenStudy (anonymous):

:D:D:D

OpenStudy (anonymous):

Thanks

OpenStudy (anonymous):

U r the best

hero (hero):

hero (hero):

x = 2.5 is where the function hits the x axis and also where y = 0 Take the integral of the function from 0 to 2.5 Then take the integral of the function from 2.5 to 4 The absolute value of their differences will be the total area under the curve of the function from 0 to 4

hero (hero):

Does it make any sense yet?

OpenStudy (anonymous):

so basically it is the change in placement

OpenStudy (anonymous):

I hope i am not stressing you out but like it is the positive area minus the negative area which is change in placenent kind of

hero (hero):

The area under the curve is essentially the combined area of the space under the curve that you see shaded in grey. Yes, it does INVOLVE subtracting the areas below the x-axis from those above the x-axis. But area simply means "region of space". I think that's what you should understand about it. You have a region of space under the curve of a function and that is what you are measuring.

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