Question

Can someone help me with Linear Equations?

Answer 1

sure.

Answer 2

y = negative three-halvesx + 4

–3x + 2y = 8

Type the first equation from the group you selected and identify the slope and the y-intercept of the equation.

Describe how you would graph this line using the slope-intercept method. Be sure to write in complete sentences.

Type the second equation from the group you selected and change the equation into slope-intercept form. Be sure to show all of your work. Identify the slope and y-intercept of the equation.

Describe how you would graph this line using the slope-intercept method. Be sure to write in complete sentences.

In a paragraph of at least three sentences, explain how the graphs of the two equations in your group are the same and how they are different. Be sure to use complete sentences.

Part B: Graph the two equations you selected in Part A.

You can choose from the following two options for graphing and submitting your equations to your instructor:

You may graph your equations by hand on a piece of graph paper and scan your work.

You may graph your equations using graphic or graphing technology that can be found in the Course Information area.

Answer 3

what grade are you and are you just beginning to learn algebra?

Answer 4

D:> I'm in Module 4 Llinear Equations from Algebra 1 D:>

Answer 5

what do u understand by a linear equation? and what do you know about slopes?

Answer 6

That was supposed to be a joke, lol

Answer 7

I don't know a lot... D:> I only know how to do writing equations in using point-slope form.

Answer 8

do you know what a slope is?

Answer 9

Way to go, this site is THE THING FOR YOU,
This site would just be the best thing for begineers like you,

Answer 10

D:> Yes.

Answer 11

Like what is Stack exchange for us is what is OS for you,

Answer 12

ok so umm you're familiar with "y=mx + c" ... right?

Answer 13

why r u still crying (sic) LOL

Answer 14

Yes.

Answer 15

"Type the first equation from the group you selected..." what group?

Answer 16

Group 1

y = negative three-halvesx + 4

–3x + 2y = 8

Group 2

y = negative 2 over 3x – 2

–2x + 3y = -6

Group 3

y = negative 1 over 3x + 3

–x + 3y = 9

Group 4

y = negative 1 over 6x + 5

–x + 6y = 30

Answer 17

so then you selected group 1... i suppose...

Answer 18

Yes.

Answer 19

hmm
y = negative three - halvesx +4 = -3 - (1/2)x + 4
y = -3 - (1/2)x + 4
y = -(1/2)x + 4 - 3
y = -(1/2)x + 1

do you agree?

Answer 20

o^o No, because what about the -3/4?

Answer 21

where from -3/4 ?

Answer 22

are u there...

Answer 23

negative three-halves?

Answer 24

negaative three = -3
halves = 1/2
negative three - halves = (-3) - (1/2)

Answer 25

It's -3/4x+4

Answer 26

...did you mean negative three / by four x + 4 ?

Answer 27

- = minus
+ = plus
/ = divided by
* = times

Answer 28

each group has 2 equations... is the second one the numeric form of the first one?