Question

Determine the sum of the infinite geometric series -1-(1/sqrt6)-(1/6)+...

Answer 1

\[\frac{a}{1-r}\]

Answer 2

What would a and r be exactly?

Answer 3

a is your first term, and r is your common ratio. in this case its the second term since the first term is a 1

Answer 4

take the negatives out and add up the terms; then apply the negative back to it

Answer 5

so it would be 1/(1-1/sqrt6) ?

Answer 6

yep; then remember your "-"

Answer 7

(-1-(1/sqrt6)-(1/6)-...) = - (1+(1/sqrt6)+(1/6)+...)

Answer 8

Okay thank you!!