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Determine the sum of the infinite geometric series -1-1/sqrt6-1/6+...
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that is a geometric series, S=a+a*q+a*q^2+.... you should first determine the value of q and then you can calculate the summation by a well-known formula
so would it be -1/(1-1/sqrt6) ?
see the q=1/sqrt(6), and as the q<1 we may write: S=a/(1-q)=-1/(1-1/sqrt(6)). so you are right
Okay! so what exactly would the sum be? i'm still a bit confused
take it easy. you are a sharp student just trust yourself. (your answer is right)
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According to my homework site it is not correct unfortunately
repeat it once again but I think that is true
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