Question

2 square root 27-3 square root 48+square root 147

Answer 1

\[2\sqrt{27}-3\sqrt{48}+\sqrt{147}\]

Answer 2

see 27=3^3 so you can write sqrt(27)=3*sqrt(3), if you write all the terms in this manner you can find the answer

Answer 3

?

Answer 4

step by step please

Answer 5

27=3^3, so you can say that sqrt(27)=sqrt(3^3)=sqrt{(3^2)*(3)}=sqrt(3^2)*sqrt(3)=3*sqrt(3), you can change the other terms in this way and then you will have an equation like that a*sqrt(3)-b*sqrt(3)+c*sqrt(3)=(a-b+c)*sqrt(3)

Answer 6

ok I am sorry

Answer 7

lets start with 48, are you agree that 48=3*4*4

Answer 8

yes

Answer 9

so sqrt(48)=sqrt(3*4*4)=sqrt(3)*sqrt(4*4)

Answer 10

so sqrt(48)=4*sqrt(3)

Answer 11

allright

Answer 12

confused about 147 how to i break it up

Answer 13

if you look at the problem you can find that you need sqrt(3) in all the terms, so first divide 147 to 3 and it becomes 49

Answer 14

you can write sqrt(147)=sqrt(3*49)=sqrt(3)*sqrt(49)=7sqrt(3)

Answer 15

k so i get\[18\sqrt{3}-12\sqrt{3}+7\sqrt{3}\]

Answer 16

no that is not true

Answer 17

ya figured it out it \[6\sqrt{3}-12\sqrt{3}+7\sqrt{3}\]

Answer 18

yes you are right, good luck.

Answer 19

thank