Question

simp. in Rad. form.
Sqrt 28

Answer 1

\[2 \sqrt7\]

Answer 2

i thought it was 4\[\sqrt{7}\]

Answer 3

so its 2sqrt7?

Answer 4

thx

Answer 5

No, there will be a \[2 \sqrt7\]

Answer 6

PLease hit good answer.

Answer 7

we can rewrite it as...sqrt(28)=sqrt(2*2*7)=(sqrt(2)^2*sqrt7)=2sqrt7

Answer 8

Correct.

Answer 9

as we know that square root of a square will cancel out each other with result 1.

Answer 10

ok thx tht explains a lot. thx to the both of you.

Answer 11

wouldnt sqrt384 be 2sqrt7?

Answer 12

just seeing if i have the hang of this

Answer 13

Here, we can write the given expression as...
sqrt(384)=sqrt(2*2*2*2*2*2*2*3)=sqrt(2^2*2^2*2^2*2*3)=2*2*2*sqrt(6)=8sqrt(6)
so..a big no for your answer

Answer 14

OK i see where i went wrong... i wrote 14 not 12. thx

Answer 15

how would you do 6*sqrt72

Answer 16

plz?

Answer 17

here we can rewrite our equation as..
6sqrt72=6*sqrt(2*2*2*3*3)=6*sqrt(2^2*3^2*2)=6*2*3sqrt(2)
36sqrt2...

Answer 18

howd you do tht. Explain.

Answer 19

here i just expend the sqrt term first...sqrt72
i started doing division by taking the least number 2 till it is not divisble more...and then 3 and then 4 and so on...
i got sqrt72=6sqrt2
now, i simpli multiplied it to 6 so..6*6sqrt2=36sqrt2

Answer 20

sqrt72=sqrt(2*2*2*3*3)=sqrt(2^2*3^2*2)=2*3sqrt(2)=6sqrt2

Answer 21

72/2=36
36/2=18
18/2=9
9/3=3
3/3=1
so...count the number of 2's and 3's needed to divide the number 72 here...and multiply then together to get the factor of the number 72

Answer 22

see i dontget that
i understand how to break it down but not how to get the # to multiply it by
would it be 2*2*2*3*3?

Answer 23

yes...exactly..!:)

Answer 24

you got it.......great!

Answer 25

so tht would be 72?
thn what would you do ?

Answer 26

?????

Answer 27

as we know that the square root of square of any number cancel out each other....like...sqrt(2^2)
as we know that we can rewrite the sqrt function as..sqrt(2^2)=(2^2)^(1/2)
so, it will become...(2)^(2*1/2).. here 2 in power cancel out each other ...we have left only 2 here...so...we need to sort out all the term from the square root here in the same way..we will get...sqrt72=sqrt(2*2*2*3*3)=sqrt(2^2*3^2*2)=(sqrt(2^2)*sqrt(3^2)*sqrt(2)=2*3sqrt2=6sqrt2
HOPE THIS WILL HELP YOU

Answer 28

(sqrt2)^2=sqrt(2^2)=2..let me know if you need more help on that?