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How do you find the anti derivative of (1-|x|)?
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if x>0, then |x|=x if x<0, then |x|=-x hope that helps
Maybe I am not asking the question right. its the intrgural from -1 to 1|dw:1323148266583:dw|\[\int\limits_{-1}^{1}(1-|X|)dx\]
Sorry does that make more sense?
\[\int\limits_{-1}^{1}|x|dx=\int\limits_{-1}^{0}(-x) dx+\int\limits_{0}^{1}(x) dx\]
\[\frac{-x^2}{2}|_{-1}^{0}+\frac{x^2}{2}|_0^1=[0-\frac{-1}{2}]+[\frac{1}{2}-0]=1\]
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so \[\int\limits_{-1}^{1}(1-|x|)dx=\int\limits_{-1}^{1}1 dx-\int\limits_{-1}^{1}|x| dx\] \[=x|^1_{-1}-1=[1-(-1)]-1=1+1-1=2-1=1\]
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